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S-Line round shoring bar with rubber foot

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Min. stroke (mm)
Max. stroke (mm)
Diameter (mm)

  • 42mm aluminium cargo bar with spring and 2000-2600mm stroke

  • anti-slip rubber foot

  • ratchet tensioner for better fastening

  • patented force display

  • Blocking capacity: 130daN

  • DEKRA certified

anodized aluminium
4,9 kg
in stock
in stock

Load securing by blocking

In case of blocking load securing the load is placed tightly next to each other - typically the foremost load is lied against the headboard -, and the free surfaces are blocked with a proper cargo control device to prevent the whole cargo from sliding. These devices are mainly bars, beams or parting wall locks, but it can be done with lashing straps also.

blocking with the sidewalls of the vehicle
Figure 1 - Simplest example, the cargo area is fully loaded. Cargo securing is provided by the sidewalls of the vehicle.
blocking of partial load
Figure 2 - In case of partial load, it is lied against the headboard and the other end is secured by vertical cargo bars.
segmented blocking
Figure 3 - Even the blocking capacity of the sidewalls or the cargo itself are not limitless. In this case the cargo must be segmented and each segment has to be secured by separate blocking devices.
blocking both ends
Figure 4 - Blocking both ends by horizontal beams and vertical cargo bars.
blocking cargo with different heights
Figure 5 - Blocking cargo with different heights by cargo bars.
blocking by lashing straps
Figure 6 - Blocking by lashing straps.

Calculations, forces

Blocking capacity - BC

The strength of cargo bars, beams and parting walls are described with BC (Blocking Capacity). This value shows the maximum force the blocking device can withstand without moving. These devices can be used to secure even heavier loads than the BC but the exact values have to be calculated.

Acceleration coefficient - c

The vehicle moves (accelerates, brakes, turns etc...) and so the cargo is effected by forces from different directions. In case of road vehicles VDI 2700 standard determines the exact values cargo securing must be planned on. The direction of the motion is important as braking can always cause stronger forces than acceleration.

acceleration coefficients in case of vehicles not exceeding 2 tonnes maximum mass
Figure 7 - Acceleration coefficients in four directions for vehicles not exceeding 2 tonnes maximum mass.
acceleration coefficients in case of vehicles between 2 - 3,5 tonnes maximum mass
Figure 8 - Acceleration coefficients in four directions for vehicles between 2 - 3,5 tonnes maximum mass.
acceleration coefficients in case of vehicles above 3,5 tonnes maximum mass
Figure 9 - Acceleration coefficients in four directions for vehicles above 3,5 tonnes maximum mass.

With the help of the load weight (Fz) and the acceleration coefficient (c) the force applied to the load (F) can be calculated with following formula:

Fz × c = F

Friction factor - μ

Friction factor between the load and the adjoining surface which decreases the force applied to the load. The bigger the friction is the more difficult for the load to move and the smaller BC needed to block the load.
Friction force (Ff) can be calulcated by the weight of the load (Fz) and the friction factor (μ).

Fz × μ = Ff
The friction factor depends the material of adjoining surfaces. The most typical surfaces and their values can be found in EN12195-1:

adjoining surfaces Friction factor - μ
sawn wood fabric base laminate/plywood 0,45
sawn wood grooved aluminium 0,4
sawn wood shrink film 0,3
sawn wood stainless steel sheet 0,3
plane wood fabric base laminate/plywood 0,3
plane wood grooved aluminium 0,25
plane wood stainless steel sheet 0,2
plastic pallet fabric base laminate/plywood 0,2
plastic pallet grooved aluminium 0,15
plastic pallet stainless steel sheet 0,15
steel and metal fabric base laminate/plywood 0,45
steel and metal grooved aluminium 0,3
steel and metal stainless steel sheet 0,2
concrete rough sawn wood battens 0,7
concrete smooth sawn wood battens 0,55
rubber 0,6
Table 1 - Friction factors of some usual goods according to EN12195-1.


The required blocking force (FB) can be calculated by the difference of the force applied to the load (F) and friction force (Ff).

FB > F - Ff
After some rearranging we can get the formula for the blocking force.
FB > (c - μ) × Fz
The number of blocking devices must be increased until the sum of their blocking capacities reaches the minimum required blocking force (FB).


Lets assume that there are 2 - with a weight of 1200 daN (1200 kg) each - identical pallets on a truck lied to its headboard. The platform is plywood and the pallets are made of wood. We have parting wall locks with 400 daN blocking capacity and because of the limited space we can use only 2 at once. How many parting wall locks we need and is it possible to secure the load under the given circumstances?

blockign example
Figure 10 - Blocking example in case of 2 identical pallets with a weight of 1200 daN (1200 kg) each.

We know Fz, which is 2x1200=2400 daN. According to EN12192-1 the acceleration coefficient (c) to the rear direction is 0,5, and the table gives us the friction factor (μ) between plywood and plane wood. It is 0,3. The original formula:
FB > (c - μ) × Fz
FB > (0,5 - 0,3) × 2400daN
FB > 480daN
So the situation can be managed with 2 blocking devices with 400daN BC.

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