S-Line round shoring bar with rubber foot
- 42mm aluminium cargo bar with spring and 2000-2600mm stroke
- anti-slip rubber foot
- ratchet tensioner for better fastening
- patented force display
- Blocking capacity: 130daN
- DEKRA certified
Load securing by blocking
In case of blocking load securing the load is placed tightly next to each other - typically the foremost load is lied against the headboard -, and the free surfaces are blocked with a proper cargo control device to prevent the whole cargo from sliding. These devices are mainly bars, beams or parting wall locks, but it can be done with lashing straps also.
Blocking capacity - BC
The strength of cargo bars, beams and parting walls are described with BC (Blocking Capacity). This value shows the maximum force the blocking device can withstand without moving. These devices can be used to secure even heavier loads than the BC but the exact values have to be calculated.
Acceleration coefficient - c
The vehicle moves (accelerates, brakes, turns etc...) and so the cargo is effected by forces from different directions. In case of road vehicles VDI 2700 standard determines the exact values cargo securing must be planned on. The direction of the motion is important as braking can always cause stronger forces than acceleration.
With the help of the load weight (Fz) and the acceleration coefficient (c) the force applied to the load (F) can be calculated with following formula:
Friction factor - μ
Friction factor between the load and the adjoining surface which decreases the force applied to the load. The bigger the friction is the more difficult for the load to move and the smaller BC needed to block the load.
Friction force (Ff) can be calulcated by the weight of the load (Fz) and the friction factor (μ).
|adjoining surfaces||Friction factor - μ|
|sawn wood||fabric base laminate/plywood||0,45|
|sawn wood||grooved aluminium||0,4|
|sawn wood||shrink film||0,3|
|sawn wood||stainless steel sheet||0,3|
|plane wood||fabric base laminate/plywood||0,3|
|plane wood||grooved aluminium||0,25|
|plane wood||stainless steel sheet||0,2|
|plastic pallet||fabric base laminate/plywood||0,2|
|plastic pallet||grooved aluminium||0,15|
|plastic pallet||stainless steel sheet||0,15|
|steel and metal||fabric base laminate/plywood||0,45|
|steel and metal||grooved aluminium||0,3|
|steel and metal||stainless steel sheet||0,2|
|concrete rough||sawn wood battens||0,7|
|concrete smooth||sawn wood battens||0,55|
The required blocking force (FB) can be calculated by the difference of the force applied to the load (F) and friction force (Ff).
Lets assume that there are 2 - with a weight of 1200 daN (1200 kg) each - identical pallets on a truck lied to its headboard. The platform is plywood and the pallets are made of wood. We have parting wall locks with 400 daN blocking capacity and because of the limited space we can use only 2 at once. How many parting wall locks we need and is it possible to secure the load under the given circumstances?
We know Fz, which is 2x1200=2400 daN. According to EN12192-1 the acceleration coefficient (c) to the rear direction is 0,5, and the table gives us the friction factor (μ) between plywood and plane wood. It is 0,3. The original formula: